SOLUTION: I am stuck and cannot seem to get this, A line passing through (5,-6) and (-9,y)is perpendicular to a line with slope 14/5. Find the value of y. A)1 B)-4 C)-2 D)-1 please I

Algebra ->  Functions -> SOLUTION: I am stuck and cannot seem to get this, A line passing through (5,-6) and (-9,y)is perpendicular to a line with slope 14/5. Find the value of y. A)1 B)-4 C)-2 D)-1 please I       Log On


   

Question 83498: I am stuck and cannot seem to get this,
A line passing through (5,-6) and (-9,y)is perpendicular to a line with slope 14/5. Find the value of y.
A)1
B)-4
C)-2
D)-1
please I am do finals
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the fact that perpendicular lines have slopes that are the negative reciprocal of each other.
So the slope of the line passing through the given points of (5, -6) and (-9, y) is going to be the negative reciprocal of 14%2F5 and this is -+5%2F14
Now you know what the slope is, you can apply the slope formulam+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 using the given points and you know that the result is going to be equal to -5%2F14.
%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+-5%2F14 Substitute the x- and y-coordinates of the given points.
%28y-%28-6%29%29%2F%28-9-5%29+=+-5%2F14 Simplify and solve for y.
%28y%2B6%29%2F%28-14%29+=+-5%2F14 Multiply both sides by -14.
y%2B6+=+5 Subtract 6 from both sides.
y+=+-1
Answer D) is the correct choice.