SOLUTION: If, in a right triangle, θ=27 ∘ and the side adjacent to θ has length 6 , how long is the hypotenuse? Round to at least 3 decimal places.

Algebra ->  Trigonometry-basics -> SOLUTION: If, in a right triangle, θ=27 ∘ and the side adjacent to θ has length 6 , how long is the hypotenuse? Round to at least 3 decimal places.       Log On


   



Question 834676: If, in a right triangle, θ=27 ∘ and the side adjacent to θ has length 6 , how long is the hypotenuse? Round to at least 3 decimal places.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If, in a right triangle, θ=27 ∘ and the side adjacent to θ has length 6 , how long is the hypotenuse? Round to at least 3 decimals.
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cos(27) = x/r = 6/hypotenuse
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0.8910 = 6/r
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r = 6/0.8910 = 6.7340
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Cheers,
Stan H.
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