SOLUTION: The height of an object tossed upward with an initial velocity of 104 feet per second is given bythe formula h = 16t^2 + 104t, where h is the height in feet and t is the time in se
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Question 834573: The height of an object tossed upward with an initial velocity of 104 feet per second is given bythe formula h = 16t^2 + 104t, where h is the height in feet and t is the time in seconds. What is the time required for the object to return to its point of departure? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! given:
h = -16t^2 + 104t
.
The "initial" point of departure is when 'h' is zero. So, set h to zero and solve for t:
0 = -16t^2 + 104t
0 = 4t(-4t + 26)
t = {0,13/2}
answer:
t = 13/2 seconds
or
t = 6.5 seconds
