SOLUTION: Could you please help me solve this problem? {{{ 3 + 3log( 3, (x^3 + 1) ) = 3^2 }}} I tried to convert it to exponent form but I got {{{ 3^9 = x^9 + 3x^6 + 3x^3 + 1 }}} and I

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Could you please help me solve this problem? {{{ 3 + 3log( 3, (x^3 + 1) ) = 3^2 }}} I tried to convert it to exponent form but I got {{{ 3^9 = x^9 + 3x^6 + 3x^3 + 1 }}} and I       Log On


   



Question 834466: Could you please help me solve this problem?
+3+%2B+3log%28+3%2C+%28x%5E3+%2B+1%29+%29+=+3%5E2+
I tried to convert it to exponent form but I got
+3%5E9+=+x%5E9+%2B+3x%5E6+%2B+3x%5E3+%2B+1+
and I don't think that's the right answer.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
+3+%2B+3log%28+3%2C+%28x%5E3+%2B+1%29+%29+=+3%5E2+
Divide by 3
+1+%2B+log%28+3%2C+%28x%5E3+%2B+1%29+%29+=+3
log%283%2C3%29+%2B+log%283%2Cx%5E3+%2B+1%29%29+=+log%283%2C27%29
log%283%2C3%28x%5E3+%2B+1%29%29+=+log%283%2C27%29
3%28x%5E3+%2B+1%29+=+27
x%5E3+%2B+1+=+9
x%5E3+=+8
x = 2 (principal value)