SOLUTION: Train a left the station at 7 a.m. And is traveling at a rate of 56 miles per hour. Train b left the same station at 8 AM traveling on a parallel track at a speed of 72 miles per h
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Question 834059: Train a left the station at 7 a.m. And is traveling at a rate of 56 miles per hour. Train b left the same station at 8 AM traveling on a parallel track at a speed of 72 miles per hour. At what time will train b catch up to train a? Answer by josgarithmetic(39616) (Show Source):
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______________speed___________time quantity____________distance
train a_______56______________t+1______________________d
train b_______72______________t________________________d
The faster train travels for less time, so you see train b had traveled t hours but train a, the slower train, had to travel for t+1 hours. The time quantity between 7AM and 8AM is 1 hour. Both trains reach some identical travel distance, d. The unknowns are d and t.
Rate*Time=Distance, the uniform rates equation for travel.
and .
Equate the two expressions for d and solve for t.
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