SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.

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Question 83369: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.

Answer by jmichau3(2) About Me  (Show Source):
You can put this solution on YOUR website!
ok well the best way to start is with an even interger.
Let 2n = an even integer
Then the next consecutive even integer will be 2n+2 and then 2n+4 will be the third.
then use what is given so come up with
(2n+4)^2 = (2n+2)^2 + 76.
Now solve for n, Which I will leave for you to do...
once you solve forn n, make sure to plug it back into your equations (ie 2n,2n+2, 2n+4) to find your consecutive numbers
If anything is unclear feel free to email me