SOLUTION: Can you please help me? The width of a rectangle is two meters more than one-third the length of the rectangle. If the perimeter of the rectangle is 50 meters, find the width and l

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Can you please help me? The width of a rectangle is two meters more than one-third the length of the rectangle. If the perimeter of the rectangle is 50 meters, find the width and l      Log On


   

Question 833623: Can you please help me? The width of a rectangle is two meters more than one-third the length of the rectangle. If the perimeter of the rectangle is 50 meters, find the width and length. You can leave the final as a fraction.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
x and y width and length

x=%281%2F3%29y%2B2; 2x%2B2y=50.
Try substitution for x.