SOLUTION: Currently in Business Calculus and I have my first test coming up. I'm a little lost with differentiation.
Differentiate.
1) y=(x^3)/
(x-1)
I would like to know the st
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-> SOLUTION: Currently in Business Calculus and I have my first test coming up. I'm a little lost with differentiation.
Differentiate.
1) y=(x^3)/
(x-1)
I would like to know the st
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Question 833563: Currently in Business Calculus and I have my first test coming up. I'm a little lost with differentiation.
Differentiate.
1) y=(x^3)/
(x-1)
I would like to know the steps to solve it. So that I may grasp the concept of differentiating equations. Thank you! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Differential of a rational function:
H(x) = f(x)/g(x)
---
H'(x) = [g(x)*f'(x) - f(x)*g'(x)]/[g(x)]^2
-------
Your Problem:
Differentiate.
1) y=(x^3)/(x-1)
----
y'(x) = [(x-1)*3x^2 - x^3(1)]/(x-1)^2
-------
= [3x^3-3x^2-x^3]/(x^2-2x+1)
----
= [2x^3-3x^2]/[x^2-2x+1]
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Cheers,
Stan H.
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