SOLUTION: Joe has $30.00 in 14 bills. How many $5.00 and $1.00 bills does he have? Show solution

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Question 833512: Joe has $30.00 in 14 bills. How many $5.00 and $1.00 bills does he have? Show solution
Answer by hovuquocan1997(83) About Me  (Show Source):
You can put this solution on YOUR website!
Let's the number of $5 bills be "x" and the number of 1$ bills be "y"
Now we have the total is 14 bills, that means x+%2B+y+=+14
Then we have the total money is $30, that means we have 5x+%2B+1y+=+30 (because x is $5 and y is $1)
Now let's solve the system of equation :)
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+14%2C%0D%0A++++5%5Cx+%2B+1%5Cy+=+30+%29%0D%0A++We'll use substitution. After moving 1*y to the right, we get:
1%2Ax+=+14+-+1%2Ay, or x+=+14%2F1+-+1%2Ay%2F1. Substitute that
into another equation:
5%2A%2814%2F1+-+1%2Ay%2F1%29+%2B+1%5Cy+=+30 and simplify: So, we know that y=10. Since x+=+14%2F1+-+1%2Ay%2F1, x=4.

Answer: system%28+x=4%2C+y=10+%29.

So Joe has 4 $5 bills and 10 $1 bills
TA-DAH
:D