SOLUTION: The first plane has 117 more seats than the 2nd plane. The third plane has 18 fewer seats than the the second plane. The total number of seats is 405.Find the the number of seats

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Question 833437: The first plane has 117 more seats than the 2nd plane. The third plane has 18 fewer seats than the the second plane. The total number of seats is 405.Find the the number of seats for each plane.
Found 2 solutions by JulietG, lwsshak3:
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
A + B + C = 405
A = B + 117 (The first plane has 117 more seats than the 2nd plane.)
C = B - 18 (The third plane has 18 fewer seats than the the second plane.)
Go back to the first equation, but substitute the values
(B+117) + B + (B-18) = 405
Add the Bs
3B +117 -18 = 405
3B +99 = 405
Subtract 99 from each side
3B = 306
Divide each side by 3
B = 102
If the second plane has 102 seats, you should be able to figure out the first and third planes :-)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
The first plane has 117 more seats than the 2nd plane. The third plane has 18 fewer seats than the the second plane. The total number of seats is 405.Find the the number of seats for each plane.
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let x=number of seats on 2nd plane
x+117=number of seats on 1st plane
x-18=number of seats on 3rd plane
x+x+117+x-18=405
3x=306
x=102
x+117=219
x-18=84
number of seats on 2nd plane=102
number of seats on 1st plane=219
number of seats on 3rd plane=84