SOLUTION: This is the system of equations problem... "Laura has $4.50 in dimes and quarters. She has 3 more dimes than quarters. How many quarters does she have?" I thought of this equat

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: This is the system of equations problem... "Laura has $4.50 in dimes and quarters. She has 3 more dimes than quarters. How many quarters does she have?" I thought of this equat      Log On


   



Question 833420: This is the system of equations problem...
"Laura has $4.50 in dimes and quarters. She has 3 more dimes than quarters. How many quarters does she have?"
I thought of this equation, but it isn't a system and I am not sure it would work either.
+%28.10x%2B3%29%2B.25y=4.5+
Could someone please explain how to solve this system of equations word problem? Thank so much and I really appreciate it.

Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
"Laura has $4.50 in dimes and quarters. She has 3 more dimes than quarters. How many quarters does she have?"
Equations:
Quantity: d = q + 3
Value::: 10d + 25q = 450 cents
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Substitute for "d" and solve for "q":
10(q+3) + 25q = 450
10q + 30 + 25q = 450
35q = 420
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q = 12 (# of quarters)
----
d = q+3 = 15 (# of dimes)
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Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Convert dollar to cents
She has 450 cents
Let d = the number of dimes she has
Let q = the number of quarters she has
-------------------
(1) +d+=+q+%2B+3+
(2) +10d+%2B+25q+=+450+
-----------------------
(1) +d+-+q+=+3+
Multiply both sides of (1) by 25+
and add (1) and (2)
(2) +10d+%2B+25q+=+450+
(1) +25d+-+25q+=+75+
+35d+=+525+
+d+=+15+
and, since
(1) +d+-+q+=+3+
(1) +q+=+d+-+3+
(1) +q+=+12+
She has 15 dimes and 12 quarters
check:
(2) +10d+%2B+25q+=+450+
(2) +10%2A15+%2B+12%2A25+=+450+
(2) +150+%2B+300+=+450+
(2) +450+=+450+
OK