SOLUTION: Jane bought a certain number of oranges at 45^c each, and the same number of oranges of oranges at 35^c each. She paid $44.00 for the oranges. How many oranges did she buy?

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Question 833333: Jane bought a certain number of oranges at 45^c each, and the same number of oranges of oranges at 35^c each. She paid $44.00 for the oranges.
How many oranges did she buy?

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
HOW TO THINK THROUGH THE PROBLEM FOR MULTIPLE CHOICE:
If she bought the same number of oranges at each price, then the average price she paid was
%2845%5Ec%2B35%5Ec%29%2F2=40%5Ec per orange, so she must have bought
%22%24+44.00%22%2F%22%24+0.40+%2F+orange%22=110oranges .

TO EXPLAIN WITH "show your work":
x= number of oranges bought at each price.
($0.45)x + ($0.35)x = $44.00
0.44x%2B0.35x+=+44
%280.44%2B0.35%29x+=+44
%280.80%29x+=+44
x=44%2F0.80
x=55
So Jane bought a total =2x=2%2A55=highlight%28110%29 oranges.