SOLUTION: if the width of a rectangle is four feet less than the length and the perimeter is 68 feet, what are the dimensions of the rectangle?
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Question 833222: if the width of a rectangle is four feet less than the length and the perimeter is 68 feet, what are the dimensions of the rectangle? Answer by JulietG(1812) (Show Source):
You can put this solution on YOUR website! P = 2L + 2W
P = 68
W = L-4
Let's plug in the values
68 = 2L + 2(L-4) [substituting the width value]
68 = 2L + 2L - 8
Add 8 to each side, and add the Ls
76 = 4L
Divide each side by 4
L = 19
.
If L = 19, then W = L-4, or 15
.
Check by putting in the numbers
68 = (2*19) + (2*15)
68 = 38 + 38
Success!
