SOLUTION: Graph this conic section. Also please include any foci, asymptotes, and vertices. (x-2)^2/36 + (y+1)^2/25 =1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Graph this conic section. Also please include any foci, asymptotes, and vertices. (x-2)^2/36 + (y+1)^2/25 =1      Log On


   

Question 832800: Graph this conic section. Also please include any foci, asymptotes, and vertices.
(x-2)^2/36 + (y+1)^2/25 =1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Graph this conic section. Also please include any foci, asymptotes, and vertices.
(x-2)^2/36 + (y+1)^2/25 =1
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Equation is that of an ellipse with horizontal major axis.
Its standard form: %28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1, a>b, (h,k)=(x,y) coordinates of center.
For given equation:
center((2,-1)
a^2=36
a=6
b^2=25
b=5
c^2=a^2-b^2=36-25=11
c=√11≈3.3
vertices: (2±a,-1)=(2±6,-1)=(-4,-1) and (8,-1)
foci:(2±c,-1)=(2±3.3,-1)=(-1.3,-1) and (5.3,-1)
see graph below:
y=((25/36)(36-(x-2)^2))^.5-2