Question 832694: cos3 + jsin3 / cos2 +jsin
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! (cos3 + jsin3) / (cos2 +jsin)
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Multiply numerator and denominator by cos(2)-jsin(2) to get:
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= [(cos(3)+jsin(3))(cos(2)-jsin(2)]/[cos^2(2)+sin^2(2)]
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= [cos(3)cos(2) + sin(3)sin(2)]/1
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= cos(3-2)
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= cos(1)
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Cheers,
Stan H.
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