SOLUTION: Hello there. I have a question regarding slopes. How do you algebraically find the equation of a line whose slope is -2/3 and contains the point (-18,14)? thanks, Max

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Question 832619: Hello there. I have a question regarding slopes. How do you algebraically find the equation of a line whose slope is -2/3 and contains the point (-18,14)?
thanks, Max
Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, Max--

THE PROBLEM:
How do you algebraically find the equation of a line whose slope is -2/3 and contains the point (-18,14)?

A SOLUTION:

Use the point-slope form. Here m is the slope, while x%5B1%5D and y%5B1%5D are the x- and y-values of a 
point on the line

y-y%5B1%5D=m%28x-x%5B1%5D%29

Substitute -2/3 for m, -18 for x%5B1%5D and 14 for y%5B1%5D.
y-14=%28-2%2F3%29%28x-%28-18%29%29

Simplify.
y-14=%28-2%2F3%29%28x%2B18%29

You can rearrange the terms to get this equation in slope-intercept form (y=mx+b) or in general form if 
you like, but this is a perfectly valid equation for the line with a slope of -2/3 that passed through the 
point(-18, 14).


Hope this helps! Feel free to email if you have any questions about the solution.

Good luck with your math,

Mrs. F
math.in.the.vortex@gmail.com