SOLUTION: can you please help me with this equation.. what is the slope and y-intercept for the line:-10x-5y+20=0

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Question 8326: can you please help me with this equation..
what is the slope and y-intercept for the line:-10x-5y+20=0
Found 2 solutions by ichudov, CrazyMan Jr.:
Answer by ichudov(507) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation -10+x+%2B+-5+y+=+-20 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+--10%2F-5.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -20/-10 = 2.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -20/-5 = 4.
  • Slope is --10/-5 = -2.
  • Equation in slope-intercept form: y=-2*x+4.
graph%28+500%2C+500%2C+2-8%2C+2%2B8%2C+4-8%2C+4%2B8%2C+-2%2Ax%2B4+%29+

Answer by CrazyMan Jr.(21) About Me  (Show Source):
You can put this solution on YOUR website!
-10x-5y+20=0
Re-arrange the equation.
-5y = 10x-20
-5y/-5 = (10x/-5)-(20/-5)
y = -2x+4
J-Man