SOLUTION: log2(x^2-x)=1

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Question 832333: log2(x^2-x)=1
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
log2(x^2-x)=1
x^2-x= 2^1
x^2-x= 2
x^2-x-2 = 0
(x+1)(x-2) = 0
x = {-1,2}