You can
put this solution on YOUR website!
I just need this multiplied and
simplified. The hashed line is
supposed to be a solid line.
(4c² - 100)(16c + 48)
-----------------------
(8c² - 72) (2c – 10)
You don't multiply, you just factor everything
and cancel!
Factor 4c² - 100
4(c² - 25)
4(c - 5)(c + 5)
Factor 16c + 48
16(c + 3)
Factor 8c² - 72
8(c² - 9)
8(c - 3)(c + 3)
Factor 2c - 10
2(c - 5)
Now replace each parentheses by its factorization:
4(c - 5)(c + 5)16(c + 3)
--------------------------
8(c - 3)(c + 3)2(c - 5)
Multiply the 4 by the 16 in the top, getting 64
Multiply the 8 by the 2 in the bottom, getting 16
64(c - 5)(c + 5)(c + 3)
-------------------------
16(c - 3)(c + 3)(c - 5)
Cancel the 16 into 64 and get 4 on top:
4
64(c - 5)(c + 5)(c + 3)
-------------------------
16(c - 3)(c + 3)(c - 5)
1
Cancel the (c - 5)'s
4 1
64(c - 5)(c + 5)(c + 3)
-------------------------
16(c - 3)(c + 3)(c - 5)
1 1
Cancel the (c + 3)'s
4 1 1
64(c - 5)(c + 5)(c + 3)
-------------------------
16(c - 3)(c + 3)(c - 5)
1 1 1
Now all that's left is
4(c + 5)
---------
c - 3
Edwin