SOLUTION: Find the real zeros of f and the x-intercepts of the graph of f. f(x) = −x2 + 5x + 24 {{{f(x)=-x^2+5x+24}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find the real zeros of f and the x-intercepts of the graph of f. f(x) = −x2 + 5x + 24 {{{f(x)=-x^2+5x+24}}}      Log On


   

Question 832116: Find the real zeros of f and the x-intercepts of the graph of f.
f(x) = −x2 + 5x + 24
f%28x%29=-x%5E2%2B5x%2B24
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Well explained in the lesson, "Completing the Square to Solve General Quadratic Equation"
http://www.algebra.com/my/Completing-the-Square-to-Solve-General-Quadratic-Equation.lesson?content_action=show_dev

Find it through my profile, lessons link.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Find the real zeros of f and the x-intercepts of the graph of f.
f(x) = −x2 + 5x + 24
f%28x%29=-x%5E2%2B5x%2B24


Factoring results in zeroes at: highlight_green%28-+3_and_8%29

Intercepts: (highlight_green%28-+3%29,highlight_green%280%29), and (highlight_green%288%29,highlight_green%280%29) 

You can do the check!! 



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