SOLUTION: x+2z=9 2y+z=8 4x−3y=−2
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Question 832047
:
x+2z=9
2y+z=8
4x−3y=−2
Answer by
TigerAlgebra(40)
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x+2z=9;2y+z=8;4x−3y=−2
{x,z,y} = {1,4,2}
Find x, y and z for the system of three equations x+2z=9 2y+z=8 4x-3y=-2 on Tiger Algebra Solver
