SOLUTION: Find an equation of the line that passes through the point (4,2) and is perpendicular to the line 4x+3y=0

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Question 832015: Find an equation of the line that passes through the point (4,2) and is perpendicular to the line 4x+3y=0
Answer by erica65404(394) About Me  (Show Source):
You can put this solution on YOUR website!
The first you need to do, is find the slope of the given line. Solve the equation for y.
4x%2B3y=0
3y=-4x
y=%28-4%2F3%29x
the slope for this line is -4%2F3
Now we need to find a slope that is perpendicular. Take the recriprocal and multiply it by -1.
-4%2F3's reciprocal is -3%2F4 and multiply it by -1 to get a slope of 3%2F4.

Now we have y=%283%2F4%29x%2Bb as the beginning of the perpendicular line. We still need to find b.
They give you the point (4,2), plug in the x and y values into the equation and solve for b.
2=%283%2F4%29%284%2F1%29+%2B+b
2+=+3+%2B+b
-1=b

now the final equation is y=%283%2F4%29x-1
If you would like more help, email me at ericahigley@yahoo.com.