SOLUTION: Find an equation of the circle that satisfies the center at origin and passes through (6,3)

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Question 831995: Find an equation of the circle that satisfies the center at origin and passes through (6,3)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The radius is the distance from (0,0) to (6,3). If you call this radius, r, then you would find some equation for your circle, x%5E2%2By%5E2=r%5E2

r%5E2=%286%5E2%29%2B%283%5E2%29=36%2B9=45, based on the pythagorean theorem and distance formula.