SOLUTION: express each of the following as the same function of a positive acute angle:
a. cos 112degrees 33'
b.tan 310degrees
c.cot 138degrees 15' 10"
d.sin (-140degrees)
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-> SOLUTION: express each of the following as the same function of a positive acute angle:
a. cos 112degrees 33'
b.tan 310degrees
c.cot 138degrees 15' 10"
d.sin (-140degrees)
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Question 83178: express each of the following as the same function of a positive acute angle:
a. cos 112degrees 33'
b.tan 310degrees
c.cot 138degrees 15' 10"
d.sin (-140degrees) Answer by Edwin McCravy(20059) (Show Source):
express each of the following as the same function
of a positive acute angle:
a. cos( 112°33')
That angle is in the second quadrant.
The cosine is negative in the second quadrant.
The reference angle is found by subtracting it from 180°
180° 179°60'
-112°30' = -112°33'
-------------------
67°27'
Therefore cos(112°33) = -cos(67°27')
--------------------------------------------
b.tan(310°)
That angle is in the fourth quadrant.
The tangent is negative in the fourth quadrant.
The reference angle is found by subtracting 310° from 360°
360°
-310
-----
50°
Therefore tan(310°) = -tan(50°)
-------------------------------------------
c.cot(138°15'10")
That angle is in the second quadrant.
The cotangent is negative in the second quadrant.
The reference angle is found by subtracting it from 180°
180° 179°59'60"
-138°15'10" = -138°15'10"
-------------------------
41°44'50"
Therefore cot(138°15'10") = -cot(41°44'50)
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d.sin (-140°)
That angle is in the third quadrant.
The sine is negative in the third quadrant.
The reference angle is found by subtracting 140° from 180°
180°
-140°
-----
40°
Therefore sin(-140°) = -sin(40°)
Edwin