SOLUTION: This one is tough for me, any help is appreciated: {{{(x^7y^4z^0)/(5^-2x^3y^-8z^-9)^2}}}

Algebra ->  Equations -> SOLUTION: This one is tough for me, any help is appreciated: {{{(x^7y^4z^0)/(5^-2x^3y^-8z^-9)^2}}}      Log On


   

Question 83164: This one is tough for me, any help is appreciated:

%28x%5E7y%5E4z%5E0%29%2F%285%5E-2x%5E3y%5E-8z%5E-9%29%5E2
Answer by Mona27(45) About Me  (Show Source):
You can put this solution on YOUR website!
First try expanding the bottom bracket (if I understand correctly the last number you put down was a power of 2)
This means that each power in the bottom expression will be multiplied by 2:
%28x%5E7y%5E4z%5E0%29%2F%285%5E-4x%5E6y%5E-16z%5E-18%29
Next deal with the numbers:
1%2F5%5E-4=5%5E4=625
Then terms in x:
x%5E7%2Fx%5E6=x
Then terms in y:
y%5E4%2Fy%5E-16=y%5E20
And finally z:
z%5E0%2Fz%5E-18=z%5E18
So it all becomes
625xy%5E20z%5E18