SOLUTION: Given the following information, write each ellipses equation in standard form. The vertices for this equation is (12,0),(-12,0) and the focii for this equation is (2 sqrt.11,0), (

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Given the following information, write each ellipses equation in standard form. The vertices for this equation is (12,0),(-12,0) and the focii for this equation is (2 sqrt.11,0), (      Log On


   



Question 831602: Given the following information, write each ellipses equation in standard form. The vertices for this equation is (12,0),(-12,0) and the focii for this equation is (2 sqrt.11,0), (-2 sqrt.11,0). What will the equation in standard form be?
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Answer by lwsshak3(11628) About Me  (Show Source):
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Given the following information, write each ellipses equation in standard form. The vertices for this equation is (12,0),(-12,0) and the focii for this equation is (2 sqrt.11,0), (-2 sqrt.11,0). What will the equation in standard form be?
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Equation is that of an ellipse with horizontal major axis and center at origin (0,0)
Its standard form: x%5E2%2Fa%5E2%2By%5E2%2Fb%5E2=1
center:(0,0)
a=12(distance from center to vertices on the major axis)
a^2=144
..
c=2√11((distance from center to vertices on the major axis)
c^2=44
c^2=a^2-b^2
b^2=a^2-c^2=144-44=100
Equation:
x%5E2%2F144%2By%5E2%2F100=1