You can put this solution on YOUR website! If sin theta= 2/3 and theta is in Quadrant I, what is the value of (tan theta)(cos theta?
-----
sin = y/r, so y = 2 and r = 3
Then x = sqrt[3^2-2^2] = sqrt(5)
------
Ans: tan(t) = y/x = 2/sqrt(5) ; cos(t) = x/r = sqrt(5)/3
=====================================
Cheers,
Stan H.
==================