Question 831570: Two fishing boats depart a harbor at the same time, one traveling east, the other south. The eastbound boat travels at a speed 7 mi/h faster than the southbound boat. After two hours the boats are 34 mi apart. Find the speed of the southbound boat.
Found 3 solutions by josgarithmetic, MathTherapy, adamhen894:
Answer by josgarithmetic(39617)   (Show Source):
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
Two fishing boats depart a harbor at the same time, one traveling east, the other south. The eastbound boat travels at a speed 7 mi/h faster than the southbound boat. After two hours the boats are 34 mi apart. Find the speed of the southbound boat.
Equation, with S being speed of southbound boat: 
Speed of southbound boat:  mph
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Answer by adamhen894(15) (Show Source):
You can put this solution on YOUR website! for the eastbound boat,
distance:2(x+7) mile
speed:(x+7)mi/h
time: 2h
for the southbound boat,
distance: 2x mile
speed: x mi/h
time: 2 h
it's a right triangle problem, the hypotenuse is 34 miles apart.
now you can set up the equation using Pythagorean theorem,
(2x)^2+(2x+14)^2=34^2
using quadratic equation to solve for x,
you get x = 8
which is speed (mi/h) of southbound boat.
let me know if you have any questions, adamchen894@gmail.com
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