SOLUTION: a unit of tasks can be completed by A, B, C, D and E in 2 hours. If it is done by A and B, it can be completed in 4 hours 48 minutes, by B, C and D in 4 hours, and by A, C and E in

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: a unit of tasks can be completed by A, B, C, D and E in 2 hours. If it is done by A and B, it can be completed in 4 hours 48 minutes, by B, C and D in 4 hours, and by A, C and E in      Log On


   



Question 831418: a unit of tasks can be completed by A, B, C, D and E in 2 hours. If it is done by A and B, it can be completed in 4 hours 48 minutes, by B, C and D in 4 hours, and by A, C and E in 3 hours 12 minutes. How long does it take for each person to complete the unit of tasks?
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
Check the problem again. A piece of information is missing.  
There are 5 unknowns, but there is only enough information 
to get 4 equations.  That's called an "underdetermined" system.
(I'm assuming you're not taking linear algebra, or are you?
I'll assume you aren't.)  We can at best get some of times, 
and we may not get any! But let's see how far we can get
without the missing piece of information.

Let The answers be:
It takes A "a" hours to complete the task alone.
It takes B "b" hours to complete the task alone.
It takes C "c" hours to complete the task alone.
It takes D "d" hours to complete the task alone.
It takes E "e" hours to complete the task alone.

Then 
A's working rate is 1 task per "a" hours or 1%2Fa tasks/hour
B's working rate is 1 task per "b" hours or 1%2Fb tasks/hour
C's working rate is 1 task per "c" hours or 1%2Fc tasks/hour
D's working rate is 1 task per "d" hours or 1%2Fd tasks/hour
E's working rate is 1 task per "e" hours or 1%2Fe tasks/hour
a unit of tasks can be completed by A, B, C, D and E in 2 hours.
So their combined working rate is  1 task per "2" hours or 1%2F2 tasks/hour

%28matrix%283%2C1%2C%22A%27s%22%2Cworking%2Crate%29%29%22%22%2B%22%22%28matrix%283%2C1%2C%22B%27s%22%2Cworking%2Crate%29%29%22%22%2B%22%22%28matrix%283%2C1%2C%22C%27s%22%2Cworking%2Crate%29%29%22%22%2B%22%22%28matrix%283%2C1%2C%22D%27s%22%2Cworking%2Crate%29%29%22%22%2B%22%22%28matrix%283%2C1%2C%22E%27s%22%2Cworking%2Crate%29%29 %22%22=%22%22 %28matrix%284%2C1%2Ctheir%2C+combined%2C+working%2Crate%29%29

So

1%2Fa%22%22%2B%22%221%2Fb%22%22%2B%22%221%2Fc%22%22%2B%22%221%2Fd%22%22%2B%22%221%2Fe %22%22=%22%22 1%2F2
If it is done by A and B, it can be completed in 4 hours 48 minutes,
4 hours and 48 minutes is 4%2B48%2F60 = 4%2B4%2F5 = 14%2F5

So their combined working rate is 1 task per 14%2F5 hours or 1%2F%2814%2F5%29 or 5%2F14 tasks/hour

%28matrix%283%2C1%2C%22A%27s%22%2Cworking%2Crate%29%29%22%22%2B%22%22%28matrix%283%2C1%2C%22B%27s%22%2Cworking%2Crate%29%29 %22%22=%22%22 %28matrix%284%2C1%2Ctheir%2C+combined%2C+working%2Crate%29%29

1%2Fa%22%22%2B%22%221%2Fb %22%22=%22%22 5%2F14
by B, C and D in 4 hours,
So their combined working rate is 1 task per 4 hours or 1%2F4 tasks/hour.

%28matrix%283%2C1%2C%22B%27s%22%2Cworking%2Crate%29%29%22%22%2B%22%22%28matrix%283%2C1%2C%22C%27s%22%2Cworking%2Crate%29%29%22%22%2B%22%22%28matrix%283%2C1%2C%22D%27s%22%2Cworking%2Crate%29%29 %22%22=%22%22 %28matrix%284%2C1%2Ctheir%2C+combined%2C+working%2Crate%29%29

1%2Fb%22%22%2B%22%221%2Fc%22%22%2B%22%221%2Fd %22%22=%22%22 1%2F4
and by A, C and E in 3 hours 12 minutes.
3 hours and 12 minutes is 3%2B12%2F60 = 3%2B1%2F5 = 16%2F5

So their combined working rate is 1 task per 16%2F5 hours or 1%2F%2816%2F5%29 or 5%2F16 tasks/hour

%28matrix%283%2C1%2C%22A%27s%22%2Cworking%2Crate%29%29%22%22%2B%22%22%28matrix%283%2C1%2C%22C%27s%22%2Cworking%2Crate%29%29%22%22%2B%22%22%28matrix%283%2C1%2C%22E%27s%22%2Cworking%2Crate%29%29%22%22=%22%22 %28matrix%284%2C1%2Ctheir%2C+combined%2C+working%2Crate%29%29

1%2Fa%22%22%2B%22%221%2Fc%22%22%2B%22%221%2Fe %22%22=%22%22 5%2F16

So we have the system of 4 equations in 5 unknowns;  



We consider the reciprocals to be the variables and
make this 4×6 augmented matrix:



Using a TI graphing calculator I get the "rref":



The third row translates as

1%2Fc=1%2F16, so c=16 and it takes C 16 hours to complete the task

So we substitute c=16 in the system



and simplify



We'll put it in a 4×5 augmented matrix.  But I'm quite 
sure that will be a singular matrix.



And get the "rref"



See? The bottom row is all 0's.

So the only answer we can get without the missing piece of
information is that C can complete the task in 16 hours.

Edwin