SOLUTION: Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time
Log On
Question 83131: Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time each day? Found 2 solutions by ankor@dixie-net.com, josmiceli:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time each.
:
Let t = time to drive 270 mi
Then (t+2) = time to drive 360 mi
:
Since she drove the same speed on both legs of the trip, write a speed equation:
Speed = Distance/Time
:
270 mi speed = 360 mi speed =
Cross multiply and you have:
360t = 270(t+2)
:
360t = 270t + 540
360t - 270t = 540
90t = 540
t = 540/90
t = 6 hr to drive 270 mi, obviously it's 8 hrs to drive 360
:
Check solution by confirming equal speeds:
270/6 = 45
360/8 = 45
:
Make sense to you? Any questions?