SOLUTION: Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time       Log On


   



Question 83131: Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time each day?
Found 2 solutions by ankor@dixie-net.com, josmiceli:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time each.
:
Let t = time to drive 270 mi
Then (t+2) = time to drive 360 mi
:
Since she drove the same speed on both legs of the trip, write a speed equation:
Speed = Distance/Time
:
270 mi speed = 360 mi speed
270%2Ft = 360%2F%28%28t%2B2%29%29
Cross multiply and you have:
360t = 270(t+2)
:
360t = 270t + 540
360t - 270t = 540
90t = 540
t = 540/90
t = 6 hr to drive 270 mi, obviously it's 8 hrs to drive 360
:
Check solution by confirming equal speeds:
270/6 = 45
360/8 = 45
:
Make sense to you? Any questions?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
360+%2F+%28t%2B2%29+=+270%2Ft
360t+=+270t+%2B+540
90t+=+540
t+=+6
t%2B2+=+8
The driving times were 8 hours and 6 hours
The speed each day was 45 mph