SOLUTION: #1.
A person standing close to the edge on the top of a 122-foot building throws a baseball vertically upward. The quadratic equation
h = -16 t^2 + 96 t + 122
models the b
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A person standing close to the edge on the top of a 122-foot building throws a baseball vertically upward. The quadratic equation
h = -16 t^2 + 96 t + 122
models the b
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Question 831087: #1.
A person standing close to the edge on the top of a 122-foot building throws a baseball vertically upward. The quadratic equation
h = -16 t^2 + 96 t + 122
models the ball's height h above the ground in feet, t seconds after it was thrown.
How high is the ball after 3 seconds?
How many seconds does it take until the ball finally hits the ground? Round to the nearest tenth of a second. Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! #1.
A person standing close to the edge on the top of a 122-foot building throws a baseball vertically upward. The quadratic equation
h = -16 t^2 + 96 t + 122
models the ball's height h above the ground in feet, t seconds after it was thrown.
How high is the ball after 3 seconds?
set t=3 and solve:
h = -16*3^2 + 96*3 + 122
h = -16*9 + 96*3 + 122
h = -144 + 288 + 122
h = 144 + 122
h = 266 feet
How many seconds does it take until the ball finally hits the ground? Round to the nearest tenth of a second.
set h=0 and solve for t:
0 = -16t^2 + 96 t + 122
solve using the quadratic formula to get:
t={-1.1, 7.1}
throw out the negative solution (extraneous) leaving:
t = 7.1 seconds
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Details of quadratic formula:
