SOLUTION: the length of a rectangle is three times its width, find the width if its perimeter is 100ft

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Question 830863: the length of a rectangle is three times its width, find the width if its perimeter is 100ft
Found 2 solutions by JulietG, josmiceli:
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
We know that the perimeter (like a fence) is 2 pieces of the length and 2 pieces of the width. P = 2L + 2W
The problem tells us that L = 3W ("length is three times its width")
The perimeter is given as 100'.
.
Now we just have to plug in the values.
100 (P) = 2L + 2W
Substitute the value for L
100 = 2(3W) + 2W
Multiply
100 = 6W + 2W
Add
100 = 8W
Divide each side by 8
12.5 = W
.
Now that we know W, we can find L ("length is three times its width")
L = 3* W (12.5)
L = 37.5
.
Let's check to be certain.
P = 2(37.5) + 2(12.5)
P = 75 + 25
100 = 75 + 25
.
Success!

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Given:+L+=+3W+
Perimeter = +2W+%2B+2L+
By substitution:
Perimeter = +2W+%2B+2%2A3W+
Perimeter = +8W+
+100+=+8W+
+W+=+12.5+
and
+L+=+3W+
+L+=+3%2A12.5+
+L+=+37.5+
-------------
The width is 12.5 ft
check:
+100+=+2%2A12.5+%2B+2%2A37.5+
+100+=+25+%2B+75+
+100+=+100+
OK