SOLUTION: If angle X is the angle of elevation from a point on the ground to the top of a tree, and if sinX=40/41 and the tree is 20 feet high, then how far from the base of the tree is the
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-> SOLUTION: If angle X is the angle of elevation from a point on the ground to the top of a tree, and if sinX=40/41 and the tree is 20 feet high, then how far from the base of the tree is the
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Question 830855: If angle X is the angle of elevation from a point on the ground to the top of a tree, and if sinX=40/41 and the tree is 20 feet high, then how far from the base of the tree is the point on the ground? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If angle X is the angle of elevation from a point on the ground to the top of a tree, and if sinX=40/41 and the tree is 20 feet high, then how far from the base of the tree is the point on the ground?
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Draw the picture:
You have a right triangle.
Base angle (X) has sin(X)= 40/41.
Side opposite is 20 ft
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Equation:
y/r = 40/41
20/r = 40/41
r = 20*41/40
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r = 20.5
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Ans: base = sqrt[20.5^2-20^2] = 4.5 ft
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Cheers,
Stan H.
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