SOLUTION: I am having a difficult time with these problems any help would be appreciated. I think I am trying to make this harder than what it is. That is usually what I do. Could you Pleas

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Question 8308: I am having a difficult time with these problems any help would be appreciated.
I think I am trying to make this harder than what it is. That is usually what I do. Could you Please show how you got the answer. Thank You!
here are the instructions:
Solve Each Equation x/2 + x/5 + x/3 = 31
Solve each formula for the indicated variable. R(r1 + r2) = r1r2, for R
Solve for x. State any restrictions on the variables. b(5px-3c) = a(qx-4)
3ax/5 - 4c= ax/5
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
1)Solve:
x%2F2+%2B+x%2F5+%2B+x%2F3+=+31 Add the fractions on the left side. Common denominator is 30.
%2815x+%2B+6x+%2B+10x%29%2F30+=+31
31x%2F30+=+31 Multiply both sides by 30.
31x+=+31%2830%29 Divide both sides by 31.
x+=+30
2)Solve R%28r1%2Br2%29+=+r1r2 for R Divide both sides by (r1+r2)
R+=+r1r2%2F%28r1%2Br2%29
3) Solve b%285px-3c%29+=+a%28qx-4%29 for x. Divide both sides by b.
5px-3c+=+a%28qx-4%29%2Fb Separate the right side into 2 terms.
5px-3c+=+aqx%2Fb+-+4a%2Fb Add 3c to both sides.
5px+=+3c+%2B+aqx%2Fb+-+4a%2Fb Subtract aqx%2Fb from both sides.
5px+-+aqx%2Fb+=+3c+-+4a%2Fb Factor the x from the left side.
x%285p+-+aq%2Fb%29+=+3c+-+4a%2Fb Simplify both sides then divide both sides by %285bp+-+aq%29%2Fb
x+=+%28%283bc-4a%29%2Fb%29%2F%28%285bp-aq%29%2Fb%29 = %28%283bc-4a%29%2Fb%29%2A%28b%2F%285bp-aq%29%29 Cancel the b's
x+=+%283bc-4a%29%2F%285bp-aq%29 Restriction: aq may not = 5bp
4) Solve 3ax%2F5+-+4c+=+ax%2F5 Add 4c to both sides.
3ax%2F5+=+ax%2F5+%2B+4c Subtract ax/5 from both sides.
2ax%2F5+=+4c Multiply both sides by 5.
2ax+=+20c Divide both sides by 2a and simplify.
x+=+10c%2Fa Restriction: a cannot = 0