SOLUTION: An express train travels 600 mi in the same amount of time it takes a freight train to travel 360 mi. The rate of the express train is 20 mph faster than that of the freight train.
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Question 83077This question is from textbook introductory algebra
: An express train travels 600 mi in the same amount of time it takes a freight train to travel 360 mi. The rate of the express train is 20 mph faster than that of the freight train. Find the rate of each train. This question is from textbook introductory algebra
You can put this solution on YOUR website! 600/(R+20)=360/R NOW WE CROSS MULTIPLY
360(R+20)=600R
360R+7200=600R
360R-600R=-7200
-240R=-7200
R=-7200/-240
R=30 MPH FOR THE FREIGHT TRAIN.
30+20=50 FOR THE EXPRESS TRAIN.
PROOF
600/50=360/30
12=12
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