SOLUTION: {{{ -(3)/(2*sqrt(x^5)) = -(3*sqrt(x))/(2x^3) }}} is true when x>0
i know that {{{ sqrt(x)=x^(1/2) }}} and that when moving a variable from the numerator to the denominator we ch
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-> SOLUTION: {{{ -(3)/(2*sqrt(x^5)) = -(3*sqrt(x))/(2x^3) }}} is true when x>0
i know that {{{ sqrt(x)=x^(1/2) }}} and that when moving a variable from the numerator to the denominator we ch
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Question 830762: is true when x>0
i know that and that when moving a variable from the numerator to the denominator we change the sign of the exponent,, yet i still can't figure how did the left part become the right part of the equation?
could you show me a step by step operation
and i've checked it at wolframalpha[dot]com [-(3)\(2*sqrt(x^5))=-(3*sqrt(x))/(2x^3)] and it says it's true so there's no error in the equation Answer by Edwin McCravy(20056) (Show Source):
Let's start with the left side and see
if we can get it in the form of the
right side:
Let's rationalize the denominator. We can't take
the square root of an odd power of x without
leaving a square root, as we could if it
were an even power of x. So let's get an even
power of x under the square root by multiplying by
. Then we will have an
even power of x under the square root and we'll be
able to take the square root just by dividing the
exponent by 2:
Edwin
