Question 830720: could you give answer with solution?:
Four men realised that if they stood in order of weight, each one would be 3 kilos heavier than the man behind him. They also realised that their average weight was 66.5 kilos. When a fifth man joined them, their average weight decreased by 1 kilo. Find a) the weight of the heaviest man and b) the weight of the fifth man.
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! let x be the weight of the first man, then
(x +(x+3) +(x+6) +(x+9)) / 4 = 66.5
4x +18 = 4*66.5
4x = 266 - 18
4x = 248
x = 62
our four men are 62, 65, 68, 71 kilos
now to determine the fifth man's weight, we use the following formula
(266 +y) / 5 = 66.5 - 1 y represents the weight of the fifth man
266 + y = 5 * (65.5)
266 + y = 327.5
y = 61.5 kilos
a) weight of heaviest man is 71 kilos
b) weight of fifth man is 61.5 kilos
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