Question 830675: Sir please help me to resolve the below question.
A concert promoter needs to make $42,000 from the sale of 1800 tickets. The promoter charges $20 for some tickets and $30 for the others.
a) If there are x of the $20 tickets sold and y of the $30 tickets sold, write and equation that states that the sum of the tickets sold is 1800.
b) How much money is received from the sale of x tickets for $20 each?
c) How much money is received from the sale of y tickets for $30 each?
d) Write an equation that states that the total amount received from the sale is 42,000 dollars?
e) Solve the equations simultaneously to find how many tickets of each type must be sold to yield the $42,000.
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! A concert promoter needs to make $42,000 from the sale of 1800 tickets. The promoter charges $20 for some tickets and $30 for the others.
a) If there are x of the $20 tickets sold and y of the $30 tickets sold, write and equation that states that the sum of the tickets sold is 1800.
b) How much money is received from the sale of x tickets for $20 each?
c) How much money is received from the sale of y tickets for $30 each?
d) Write an equation that states that the total amount received from the sale is 42,000 dollars?
e) Solve the equations simultaneously to find how many tickets of each type must be sold to yield the $42,000.
a. x+y=1800
b. 20x
c.30y
d. 20x+30y=42000
x= number of $20 tickets
y= number of $30 tickets
1 x + 1 y = 1,800 .............1
Total value
20 x + 30 y = 42,000 .............2
Eliminate y
multiply (1)by -30
Multiply (2) by 1
-30 x -30 y = -54,000
20 x + 30 y = 42,000
Add the two equations
-10 x = -12,000
/ -10
x = 1,200
plug value of x in (1)
1 x + 1 y = 1,800
1,200 + y = 1,800
y = 1,800 -1,200
y = 600
y = 600
x= 1200 number of $20 tickets
y= 600 number of $30 tickets
m.ananth@hotmail.ca
|
|
|
