SOLUTION: 0 2pi: sin^2(x)-sq root of 3 sin(x)+1=cos^2(x)

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Question 830596: 0 2pi: sin^2(x)-sq root of 3 sin(x)+1=cos^2(x)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
[0,2pi]: sin^2(x)-sq root of 3 sin(x)+1=cos^2(x)
..
sin%5E2%28x%29-sqrt%283%29sin%28x%29%2B1=cos%5E2%28x%29
sin%5E2%28x%29-sqrt%283%29sin%28x%29%2B1=1-sin%5E2%28x%29
2sin%5E2%28x%29-sqrt%283%29sin%28x%29=0
sin%28x%29%282sin%28x%29-sqrt%283%29%29=0
..
sin(x)=0
x=0,π
or
2sin(x)-√3=0
sin(x)=√3/2
x=π/3,2π/3 (in quadrants I and II in which sin>0.