SOLUTION: Please help me solve for sin(theta)
1. cot(theta)=-1/5, (theta) is in quadrant IV
2. tan(theta)=-sqrt7/2, sec(theta)>0
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-> SOLUTION: Please help me solve for sin(theta)
1. cot(theta)=-1/5, (theta) is in quadrant IV
2. tan(theta)=-sqrt7/2, sec(theta)>0
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Question 830544: Please help me solve for sin(theta)
1. cot(theta)=-1/5, (theta) is in quadrant IV
2. tan(theta)=-sqrt7/2, sec(theta)>0 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Please help me solve for sin(theta)
1. cot(theta)=-1/5, (theta) is in quadrant IV
tan(theta) = -5
theta = arctan(-5) = -1.3734 or -78.69 degrees
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2. tan(theta)=-sqrt7/2, sec(theta)>0
With those conditions theta is in QIV
arctan(-sqrt(7)/2) = -0.9235 radians or -52.91 degrees
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Cheers,
Stan H.
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