SOLUTION: For y=x^2+2x-8, find the vertex by completing the square, find the y-intercept, find the x-intercepts, and sketch the graph

Algebra ->  Graphs -> SOLUTION: For y=x^2+2x-8, find the vertex by completing the square, find the y-intercept, find the x-intercepts, and sketch the graph      Log On


   

Question 830534: For y=x^2+2x-8, find the vertex by completing the square, find the y-intercept, find the x-intercepts, and sketch the graph
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Look at the lesson linked through my profile, "Completing the Square to Solve General Quadratic Equation". You will want to change goal a little bit and put the equation into standard form, from which you can read the vertex point coordinates. The x-intercepts are the general solutions to a quadratic formula. For y-intercept, just let x=0, which you can do with the general form equation which you are given.





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x intercepts:
x=%28-2%2B-+sqrt%282%5E2-4%28-8%29%29%29%2F%282%29;
just compute the two values.