SOLUTION: If the 10th term of a geometric sequence is 243 times larger than the 5th term, what is the common ratio of the sequence?

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Question 830500: If the 10th term of a geometric sequence is 243 times larger than the 5th term, what is the common ratio of the sequence?
Answer by reviewermath(1029) About Me  (Show Source):
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Q:
If the 10th term of a geometric sequence is 243 times larger than the 5th term, what is the common ratio of the sequence?
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A:
nth term: a%5Bn%5D+=+%28a%5B1%5D%29%28r%5E%28n-1%29%29
5th term: a%5B5%5D+=+%28a%5B1%5D%29%28r%5E4%29
10th term: a%5B10%5D+=+%28a%5B1%5D%29%28r%5E9%29
a%5B10%5D%2Fa%5B5%5D = %28a%5B1%5D%29%28r%5E9%29%2F%28a%5B1%5D%29%28r%5E4%29+=+r%5E5+=+243
Therefore, the common ratio is r = highlight%283%29.