SOLUTION: 2log base1/2 3 - log base1/2(2x-3) = 1
solving for x
I get to here: log base1/2 9/2x-3 = 1
and should get to this step next: 9/2x-3=(1/2)exponent1 and don't understand how that
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-> SOLUTION: 2log base1/2 3 - log base1/2(2x-3) = 1
solving for x
I get to here: log base1/2 9/2x-3 = 1
and should get to this step next: 9/2x-3=(1/2)exponent1 and don't understand how that
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Question 830345: 2log base1/2 3 - log base1/2(2x-3) = 1
solving for x
I get to here: log base1/2 9/2x-3 = 1
and should get to this step next: 9/2x-3=(1/2)exponent1 and don't understand how that happens or how to solve for x, which happens to be a fraction
thanks,
Wyatt Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 2log base1/2 (3) - log base1/2(2x-3) = 1
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log1/2(3^2) - log1/2(2x-3) = 1
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log1/2[9/2x-3] = 1
----
9/(2x-3) = (1/2)
----
2x-3 = 18
2x = 21
x = 11.5
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Cheers,
Stan H.
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