Question 830344: x^2+x-12<0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! x^2+x-12<0
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(x+4)(x-3) < 0
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Draw a number line:
Plot x = -4 and x = 3
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Test for solutions in the 3 line intervals:
(x+4)(x-3) < 0
Test x = -10 you get: -*- < 0 ; false
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Test x = 0 you get: +*- < 0 ; true
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Test x = 10 you get: +*+ < 0 ; false
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Solution: -4 < x < 3
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Cheers,
Stan H.
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