SOLUTION: Please solve this, "is perpendicular to the line 4y-3x=0 and contains the point (-1,3)" Thank you so much!

Algebra ->  Graphs -> SOLUTION: Please solve this, "is perpendicular to the line 4y-3x=0 and contains the point (-1,3)" Thank you so much!      Log On


   



Question 830233: Please solve this, "is perpendicular to the line 4y-3x=0 and contains the point (-1,3)" Thank you so much!
Found 2 solutions by TimothyLamb, erica65404:
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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given:
perpendicular to: 4y-3x=0
through: (-1,3)
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4y-3x=0
4y=3x
y=(3/4)x
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slope of perpendicular line: (-4/3) = -1.333333
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to solve the linear equation, copy and paste this (the given point and perpendicular slope):
-1,3,-1.333333
into the "Point-Slope form: x1 y1 m" input box here: https://sooeet.com/math/linear-equation-solver.php
---
x-intercept = (1.25, 0)
y-intercept = (0, 1.666666)
slope = (-4/3) = -1.333333
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answer:
the slope-intercept form of our new perpendicular line:
y = (-4/3)x + 1.666666
---
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---
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---
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Answer by erica65404(394) About Me  (Show Source):
You can put this solution on YOUR website!
The first step is to put this in slope-intercept form; y=mx%2Bb
4y-3x=0
4y=3x
y=%283%2F4%29x

The slope for this line is 3%2F4.

A line that is perpendicular would be the reciprocal times -1.

3%2F4's reciprocal is 4%2F3 and times that by -1, and you get the slope of -4%2F3.

So the new line line looks like y=%28-4%2F3%29x%2Bb. We still need to find b so plug the point (-1,3) in for the x and y values.

3=%28-4%2F3%29%28-1%29%2Bb
3=%284%2F3%29+%2B+b
3-%284%2F3%29=b
1%282%2F3%29=b

y=%28-4%2F3%29x+%2B+1%282%2F3%29
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