SOLUTION: Use the equation y=a*(x+4)^2+2 to find the equation whose curve passes through the origin.

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Question 829841: Use the equation y=a*(x+4)^2+2 to find the equation whose curve passes through the origin.
Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
y=a*(x+4)^2+2
to pass through the origin (0,0) we need x = 0 and y = 0
0=a*(0+4)^2+2
0=a(4^2)+2
0=a(16)+2
add -2 to each side
-2=16a
divide each side by 16
-2/16=a
a = -1/8
substituting in y=a*(x+4)^2+2
0=(-1/8)(0+4)+2
0=(-1/8)(4)+2
0=-2+2
So the value of a that will produce an equation that passes through
the origin is -1/8
The equation we want is
y=(-1/8)(x+4)^2+2