Question 829803: On the first day of a recent coin drive, Mr.Li's AP class collected a total of 17.90. When he looked in the box, he found only quarters, dimes, and nickels. If there were 1/2 as many nickels as quarters, and 10 more dimes than nickels, how many of each coin did Mr. Li's class collect?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
x = nickels
y = dimes
z = quarters
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5x + 10y + 25z = 1790
x = 0.5z
y = x + 10
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put the system of linear equations into standard form:
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5x + 10y + 25z = 1790
x - 0.5z = 0
x - y = -10
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solution:
x = nickels = 26
y = dimes = 36
z = quarters = 52
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