SOLUTION: Log(base 10)16-log(base10)(2t)=log(base 3)10

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Question 829796: Log(base 10)16-log(base10)(2t)=log(base 3)10
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Log(base 10)16-log(base10)(2t)=log(base 3)10
log%28%2816%29%29-log%28%282t%29%29=log%283%2C%2810%29%29
log%28%2816%2F2t%29%29=2.0959
10^(2.0959)≈16/2t
124.7096≈16/2t
2t≈0.1283
t≈0.0641