SOLUTION: I would greatly appreciate if someone could answer this problem for me...I'm not to sure how to begin, I was asked to solve the equation: Log5(x+4)+log5 8=log5 64

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I would greatly appreciate if someone could answer this problem for me...I'm not to sure how to begin, I was asked to solve the equation: Log5(x+4)+log5 8=log5 64      Log On


   

Question 829649: I would greatly appreciate if someone could answer this problem for me...I'm not to sure how to begin, I was asked to solve the equation:
Log5(x+4)+log5 8=log5 64
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Log5(x+4)+log5 8=log5 64
log%285%2C%28x%2B4%29%29%2Blog%285%2C%288%29%29-log%285%2C%2864%29%29=0
..
log%285%2C%28%28x%2B4%29%288%29%2F%2864%29%29%29=0
..
log%285%2C%28%28x%2B4%29%2F%288%29%29%29=0
5^0=(x+4)/8
(x+4)/8=1
x+4=8
x=4