SOLUTION: I have a fairly complex problem that I could use some help on: Tide heights can be modeled by a certain cosine function. Low tide is when the tide is at the lowest point and hig

Algebra ->  Trigonometry-basics -> SOLUTION: I have a fairly complex problem that I could use some help on: Tide heights can be modeled by a certain cosine function. Low tide is when the tide is at the lowest point and hig      Log On


   



Question 829465: I have a fairly complex problem that I could use some help on:
Tide heights can be modeled by a certain cosine function. Low tide is when the tide is at the lowest point and high tide is the tide at the highest point.
Use the function +y=+1.6%2B1.6cos%28%28%282pi%29%2F%2812.4%29%29%2At%29+ to serve as a model for the tides. Vertical units are measured in meters and t is the number of hours past high tide.
Then, answer these questions:
#1 - What is the measured difference between low and high tide?
#2 - How much time elapses between two consecutive high tides?
#3 - What is the change in water level from t = 2.5 to t = 3.5 hours? (Round to nearest hundredth of a meter)

Found 2 solutions by oscargut, stanbon:
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
#1
Answer 3.2

If you need more help you can contact me at
mthman@gmail.com
Thanks

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Use the function y= 1.6+1.6*cos(((2pi)/(12.4))*t) to serve as a model for the tides. Vertical units are measured in meters and t is the number of hours past high tide.
Then, answer these questions:
#1 - What is the measured difference between low and high tide?
low = -1.6+1.6 = 0
high = 1.6+1.6 = 3.2
-------------------------
#2 - How much time elapses between two consecutive high tides?
Period = (2pi)/[(2pi/12.4)] = 12.4 hours
-------------------------------------------------
#3 - What is the change in water level from t = 2.5 to t = 3.5 hours? (Round to nearest hundredth of a meter)
f(2.5) = 1.6+1.6cos((2pi/12.4)*2.5) = 2.0790
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f(3.5) = 1.6+1.6cos((2pi/12.4)*3.5) = 1.2779
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graph%28400%2C400%2C-6%2C6%2C-5%2C5%2C1.6%2B1.6%2Acos%28%282pi%2F12.4%29x%29%29
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Cheers,
Stan H.